Как разместить функцию по определенному адресу в C без использования #pragma? ⇐ C++

[Гость]

I want to place a function

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void loadableSW (void)

at a specific location:

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0x3FF802

. In another function

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residentMain()

I will jump to this location using pointer to function. How to declare function

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loadableSW

to accomplish this. I have attached the skeleton of

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residentMain

for clarity.

Update: Target hardware is TMS320C620xDSP. Since this is an aerospace project, deterministic behaviour is a desirable design objective. Ideally, they would like to know what portion of memory contains what at a particular time. The solution as I just got to know is to define a section in memory in the linker file. The section shall start at

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0x3FF802

(Location where to place the function). Since the size of the

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loadableSW

function is known, the size of the memory section can also be determined. And then the directive

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#pragma CODESECTION ("function_name", "section_name")

can place that function in the specified section.

Since

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pragma

directives are not permissible in test scripts, I am wondering if there is any other way to do this without using any linker directives.

Besides I am curious. Is there any placement syntax for functions in C++? I know there is one for objects, but functions?

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    void residentMain (void)     {         void (*loadable_p) (void) = (void (*) (void)) 0x3FF802;         int hardwareOK = 0;              /*Code to check hardware integrity. hardwareOK = 1 if success*/              if (hardwareOK)         {             loadable_p (); /*Jump to Loadable Software*/         }         else         {             dspHalt ();         }     } 

Источник: https://stackoverflow.com/questions/197 ... ing-pragma