403 Запрещенная ошибка при получении изображений кошек ⇐ Python

[Anonymous]

Я только что закончил программирование программы для фотографий собак, и после нескольких проблем она работает нормально. Я решил сделать модифицированную версию, которая вместо этого использует другой API для предоставления изображений кошек. Потребовалась секунда, чтобы понять, но после изменения формата я получаю эту ошибку: urllib.error.HTTPError: Ошибка HTTP 403: запрещено
Эта ошибка постоянна и возникает каждый раз.
Вот весь мой код, так как ни один из этих ответов не помог.

Код: Выделить всё

import tkinter, urllib.request, json
from PIL import Image, ImageTk

#Create the main window
main = tkinter.Tk()
main.geometry('550x600+800+300')
main.title('Dogs')

#This is the list of dog image urls
urllist = []

#This is the list of dog images
doglist = []

#This is a pointer to the image in the list, which is used as the image in the label
dognumber = 0

#Set W and H to the max width and height we want for the images
W, H = 500, 460

#Resize the image to the max width and height
def resize_image(img):
ratio = min(W/img.width, H/img.height)
return img.resize((int(img.width*ratio), int(img.height*ratio)), Image.ANTIALIAS)

#Change dog number by -1 to go back a dog, then set the image to the new dog
def last_image():
global doglist, dognumber

#This is pretty self explanatory
dognumber -= 1

#If the dog number is less than 0, set it to 0 so there's no negative indexing in dog list
if dognumber < 0:
dognumber = 0

#Set the image to the new dog
l.config(image=doglist[dognumber])

def fetch_image():
global doglist, dognumber, urllist
try:
#If the dog number is less than the length of the list, simply increment it by 1 and set the image to the new dog.  This allows you to go back a dog, and then go forward again, instead of generating a new dog every time
dognumber += 1
l.config(image=doglist[dognumber])
except IndexError:
#Even if we are on the last dog on the list, that try script will add one to the dog number, so we need to subtract one to get the correct index
dognumber -= 1

#Get the actual image of the dog we want
dogapi = urllib.request.Request(f'https://api.thecatapi.com/v1/images/search')
dogapi.add_header("x-api-key", "blahblahblah12312")
dogjson = urllib.request.urlopen(dogapi).read()
dogdict = json.loads(dogjson)
url = dogdict[0]['url']
print(url)

#Convert the image to a PIL image
#error right here, stack overflow didnt help ):
m = urllib.request.urlopen(url)
mpi = resize_image(Image.open(m))
tkimg = ImageTk.PhotoImage(mpi)

#Add the new dog to the list, as well as the url
doglist.append(tkimg)
urllist.append(url)

#Increment the dog number, and set the image to the new dog
dognumber += 1
l.config(image=tkimg)
l.image = tkimg

def save_dogs():
global urllist

#Open the file to write to
w = open('/'.join(__file__.split("\\")[:-1]) + '/doglist.txt', 'w')

#Write the urls to the file
w.write('\n'.join(urllist))

#Load Label and Buttons
l = tkinter.Label(main, image=tkinter.PhotoImage(), width=W, height=H)
b = tkinter.Button(main, text='Next Dog', command=fetch_image)
b2 = tkinter.Button(main, text='Last Dog', command=last_image)
b3 = tkinter.Button(main, text='Save Dogs', command=save_dogs)

def preloaddogs():
global doglist, dognumber, urllist
for _ in range(5):
#This does the same thing as fetch_image, but it doesn't increment the dog number so you dont end up on the last dog, and it sets the image shown to the first dog
dogapi = urllib.request.urlopen(f'https://dog.ceo/api/breeds/image/random')
dogjson = dogapi.read()
dogdict = json.loads(dogjson)
url = dogdict['message']
m = urllib.request.urlopen(url)
mpi = resize_image(Image.open(m))
tkimg = ImageTk.PhotoImage(mpi)
doglist.append(tkimg)
urllist.append(url)
url = urllist[0]
m = urllib.request.urlopen(url)
mpi = resize_image(Image.open(m))
tkimg = ImageTk.PhotoImage(mpi)
l.config(image=tkimg)
l.image = tkimg

#Load the widgets, and then preload the first 5 dogs
l.pack()
b.place(x=350, y=500)
b2.place(x=150, y=500)
b3.pack()

#preloaddogs()

main.mainloop()

И вот полная ошибка:

Код: Выделить всё

Traceback (most recent call last):
File "C:\Users\doubl\AppData\Local\Programs\Python\Python310\lib\tkinter\__init__.py", line 1921, in __call__
return self.func(*args)
File "g:\My Drive\Code\Projects\Dog\cats.pyw", line 58, in fetch_image
m = urllib.request.urlopen(url)
File "C:\Users\doubl\AppData\Local\Programs\Python\Python310\lib\urllib\request.py", line 216, in urlopen
return opener.open(url, data, timeout)
File "C:\Users\doubl\AppData\Local\Programs\Python\Python310\lib\urllib\request.py", line 525, in open
response = meth(req, response)
File "C:\Users\doubl\AppData\Local\Programs\Python\Python310\lib\urllib\request.py", line 634, in http_response
response = self.parent.error(
File "C:\Users\doubl\AppData\Local\Programs\Python\Python310\lib\urllib\request.py", line 563, in error
return self._call_chain(*args)
File "C:\Users\doubl\AppData\Local\Programs\Python\Python310\lib\urllib\request.py", line 496, in _call_chain
result = func(*args)
File "C:\Users\doubl\AppData\Local\Programs\Python\Python310\lib\urllib\request.py", line 643, in http_error_default
raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 403: Forbidden

Я попробовал добавить ключ API, но все равно получаю ту же ошибку.
Потом попробовал добавить его в заголовок, та же история.

Подробнее здесь: https://stackoverflow.com/questions/719 ... cat-images