Код: Выделить всё
SELECT suma.customerNumber, suma.Tot
FROM (
SELECT DISTINCT payments.customerNumber, ROUND(SUM(payments.amount), 2) AS Tot
FROM payments
GROUP BY customerNumber
ORDER BY Tot DESC
) suma
WHERE suma.Tot = (SELECT MAX(Tot) FROM suma)
GROUP BY suma.customerNumber;
Подробнее здесь: https://stackoverflow.com/questions/798 ... gest-value
Мобильная версия