Десятичное в бинарное преобразование ⇐ C++

[Anonymous]

Я написал программу, которая преобразует десятичную в бинар. Я уверен, что есть более простой способ, так что вы можете показать мне? < /P>
#include
#include

using namespace std;
int a1, a2, remainder;
int tab = 0;
int maxtab = 0;
int table[0];
int main()
{
system("clear");
cout > a1;
a2 = a1; //we need our number for later on so we save it in another variable

while (a1!=0) //dividing by two until we hit 0
{
remainder = a1%2; //getting a remainder - decimal number(1 or 0)
a1 = a1/2; //dividing our number by two
maxtab++; //+1 to max elements of the table
}

maxtab--; //-1 to max elements of the table (when dividing finishes it adds 1 additional elemnt that we don't want and it's equal to 0)
a1 = a2; //we must do calculations one more time so we're gatting back our original number
table[0] = table[maxtab]; //we set the number of elements in our table to maxtab (we don't get 10's of 0's)

while (a1!=0) //same calculations 2nd time but adding every 1 or 0 (remainder) to separate element in table
{
remainder = a1%2; //getting a remainder
a1 = a1/2; //dividing by 2
table[tab] = remainder; //adding 0 or 1 to an element
tab++; //tab (element count) increases by 1 so next remainder is saved in another element
}

tab--; //same as with maxtab--
cout =0) //until we get to the 0 (1st) element of the table
{
cout

Подробнее здесь: https://stackoverflow.com/questions/227 ... converting