Почему я не могу увеличить переменную перечислимого типа? ⇐ C++

[Гость]

У меня есть перечислимый тип,

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StackID

, and I am using the enumeration to refer to an index of a particular vector and it makes my code easier to read.
However, I now have the need to create a variable called

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nextAvail

of type

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StackID

(it actually refers to a particular stackID ). I tried to increment it, but in C++ the following is illegal:

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nextAvail++;

Which sort of makes sense to me ... because there isn't any bounds checking.
I'm probably overlooking something obvious, but what's a good substitute?

I also want to link to this question.


Источник: https://stackoverflow.com/questions/347 ... rated-type