Как преобразовать изображения в формат, требуемый для Open XML ⇐ C#

[Anonymous]

Следующая строка - это код, с г е н е р и р о в а н н ы й и н с т р у м е н т о м O p e n X M L S D K 2 . 5 ； < / p > < b r / > < c o d e > u s i n g D o c u m e n t F o r m a t . O p e n X m l . P a c k a g i n g ; < b r / > < b r / > n a m e s p a c e G e n e r a t e d C o d e < b r / > { < b r / > p u b l i c c l a s s G e n e r a t e d C l a s s < b r / > { < b r / > / / A d d s c h i l d p a r t s a n d g e n e r a t e s c o n t e n t o f t h e s p e c i f i e d p a r t . < b r / > p u b l i c v o i d C r e a t e I m a g e P a r t ( I m a g e P a r t p a r t ) < b r / > { < b r / > G e n e r a t e P a r t C o n t e n t ( p a r t ) ; < b r / > < b r / > } < b r / > < b r / > / / G e n e r a t e s c o n t e n t o f p a r t . < b r / > p r i v a t e v o i d G e n e r a t e P a r t C o n t e n t ( I m a g e P a r t p a r t ) < b r / > { < b r / > S y s t e m . I O . S t r e a m d a t a = G e t B i n a r y D a t a S t r e a m ( p a r t D a t a ) ; < b r / > p a r t . F e e d D a t a ( d a t a ) ; < b r / > d a t a . 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A f A A A A A A A A A A w A A A A A A A A A 5 C e H I v p / A A B 4 d R O B K w A A A A E A A A A A A A A A A A A A A A A A A A B h J A A m A A A A A M B z E 4 E r A A A A A A A A A A A A A A A A A A A A A A A A A I B I I c Y r A Q A A A A A A A A A A A A B 3 Z 5 Q n + n 8 A A K B z E 4 E r A A A A e H U T g Q A A A A A A A A A A A A A A A F i I E 4 E r A A A A A A A A A A A A A A B L V A M l + n 8 A A F B 0 E 4 E r A A A A a X Q T g S s A A A B 4 d R O B K w A A A A A A A A B k d g A I A A A A A C U A A A A M A A A A A Q A A A B g A A A A M A A A A A A A A A B k A A A A M A A A A / / / / A H I A A A C g E A A A D g A A A A A A A A A t A A A A H w A A A A 4 A A A A A A A A A I A A A A C A A A A A A g P 8 B A A A A A A A A A A A A A I A / A A A A A A A A A A A A A I A / A A A A A A A A A A D / / / 8 A A A A A A G w A A A A 0 A A A A o A A A A A A Q A A A g A A A A I A A A A C g A A A A g A A A A I A A A A A E A I A A D A A A A A B A A A A A A A A A A A A A A A A A A A A A A A A A A A P 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private System.IO.Stream GetBinaryDataStream(string base64String)
{
return new System.IO.MemoryStream(System.Convert.FromBase64String(base64String));
}

#endregion

}
}
< /code>
Я думаю, что PartData - это строка Base64, и я использовал следующий метод для генерации строки, но это несовместимо < /p>
public static string ImageToBase64(string imagePath)
{

using (FileStream fs = new FileStream(imagePath, FileMode.Open))
{
byte[] bytes = new byte[fs.Length];
fs.Read(bytes, 0, bytes.Length);
string base64String = Convert.ToBase64String(bytes);
return base64String;
}
}


Подробнее здесь: https://stackoverflow.com/questions/796 ... y-open-xml