Получение NoSuchFile или Directory в подпроцессе ⇐ Python

[Гость]

I'm trying to run a CLI tool using

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subprocess.run()

, but i'm getting irrelevant responses.

Folder structure

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script.py mytools  |__tool_x  |__tool_y 

Case:1 Try to run the below command

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import os import subprocess command = ["mytools/tool_x", "--help"] subprocess.run(                  command,                  stdout=subprocess.DEVNULL,                  cwd=os.path.dirname(__file__),              ) 

Result: It works as expected, gives no error.

Case-2:

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import os import subprocess command = ["mytools/tool_x", "--subcommand", "test", "--subarg"] subprocess.run(                  command,                  stdout=subprocess.DEVNULL,                  cwd=os.path.dirname(__file__),              ) 

Result: Fails with

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FileNotFoundError: [Errno 2] No such file or directory: 'mytools/tool_x'"

How can i resolve this, not able to find the issue, generally what are the possibilities for this issue?


Источник: https://stackoverflow.com/questions/781 ... subprocess