Как портативно заставить NAN * ноль давать ноль в конкретном выражении без ветвления? ⇐ C++
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Anonymous
Как портативно заставить NAN * ноль давать ноль в конкретном выражении без ветвления?
In general, (quiet) NAN times zero should give NAN -- and it does.
However, in one particular performance-critical part of my code, I want zero times anything to be zero.
What's a fast way to do this in C++?
Источник: https://stackoverflow.com/questions/208 ... without-br
In general, (quiet) NAN times zero should give NAN -- and it does.
However, in one particular performance-critical part of my code, I want zero times anything to be zero.
What's a fast way to do this in C++?
Источник: https://stackoverflow.com/questions/208 ... without-br
