Как я могу отправить ввод клавиши Ctrl-l в диалоговое окно выбора файла Chrome с помощью at-spi2? ⇐ Linux

[Гость]

I want to control chromium file chooser dialog without any human intervention on Linux.

I am trying to achieve it with at-spi2 and python. (at-spi2 python binding that made by gobject-intropection)

I would like to show an textbox to enter the file path directly with Ctrl-L.
But I have no idea how to send Ctrl-L to the file chooser dialog box.

Now I know the dialog box do not belong under the chromium, actually it is controlled by xdg-desktop-portal-gnome.

How I can do it?

My environment is ArchLinux and Gnome 45, Chromium 122.0.6261.94 (Official Build)

The following code is I tried send keyboard input with generate_keyboard_event, but nothing to happen...
def search_chrome_filechooser(): if not Atspi.is_initialized(): err = Atspi.init() if err != 0: print("Something Error:", err) return root = Atspi.get_desktop(0) app = search_widget(root, "xdg-desktop-portal-gnome", "application") if app == None: print("app not found") return dialog = search_widget(app, role_name="dialog") if dialog is None: print("file chooser dialog not found") if Atspi.is_initialized(): Atspi.exit() return Atspi.generate_keyboard_event(Atspi.ModifierType.CONTROL, None, Atspi.KeySynthType.LOCKMODIFIERS) Atspi.generate_keyboard_event(38, None, Atspi.KeySynthType.PRESS) Atspi.generate_keyboard_event(Atspi.ModifierType.CONTROL, None, Atspi.KeySynthType.UNLOCKMODIFIERS) Atspi.generate_keyboard_event(38, None, Atspi.KeySynthType.PRESSRELEASE) if Atspi.is_initialized(): Atspi.exit() def search_widget(root, name: str|None=None, role_name:str|None=None): widget = root if widget == None: return None if name == None and role_name == None: return widget_name = widget.get_name() widget_role_name = widget.get_role_name() if name == widget_name and role_name == None: return widget elif name == None and role_name == widget_role_name: return widget elif name == widget_name and role_name == widget_role_name: return widget num = widget.get_child_count() for v in range(num): child = widget.get_child_at_index(v) if (result := search_widget(child, name, role_name)) != None: return result search_chrome_filechooser()

Источник: https://stackoverflow.com/questions/781 ... th-at-spi2