Any — это то же самое, что Forall a.a? [закрыто] ⇐ Python
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Any — это то же самое, что Forall a.a? [закрыто]
Python has the Any type which is 'is-consistent' with any type. Isn't it possible to express Any using the type represented in Haskell as forall a.a instead of adding a new type?
Источник: https://stackoverflow.com/questions/781 ... forall-a-a
Python has the Any type which is 'is-consistent' with any type. Isn't it possible to express Any using the type represented in Haskell as forall a.a instead of adding a new type?
Источник: https://stackoverflow.com/questions/781 ... forall-a-a
