Исключение быстрой принудительной развертки не распространяется ⇐ IOS
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Anonymous
Исключение быстрой принудительной развертки не распространяется
I've run into this silly behaviour in swift where force-unwrapping an optional does not propagate.
From the documentation:
Trying to use ! to access a non-existent optional value triggers a runtime error. Always make sure that an optional contains a non-nil value before using ! to force-unwrap its value.
To reproduce:
func foo(bar:String?) throws{ print(bar!); } And
try foo(nil); This does not seem logical or consistent to me and I can't find any documentation on this subject.
Is this by design?
Источник: https://stackoverflow.com/questions/346 ... propagated
I've run into this silly behaviour in swift where force-unwrapping an optional does not propagate.
From the documentation:
Trying to use ! to access a non-existent optional value triggers a runtime error. Always make sure that an optional contains a non-nil value before using ! to force-unwrap its value.
To reproduce:
func foo(bar:String?) throws{ print(bar!); } And
try foo(nil); This does not seem logical or consistent to me and I can't find any documentation on this subject.
Is this by design?
Источник: https://stackoverflow.com/questions/346 ... propagated
