Как проверить URL-адрес в Python? (Неправильно сформирован или нет) ⇐ Python
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Anonymous
Как проверить URL-адрес в Python? (Неправильно сформирован или нет)
I have url from the user and I have to reply with the fetched HTML.
How can I check for the URL to be malformed or not?
For example :
url = 'google' # Malformed url = 'google.com' # Malformed url = 'http://google.com' # Valid url = 'http://google' # Malformed
Источник: https://stackoverflow.com/questions/716 ... med-or-not
I have url from the user and I have to reply with the fetched HTML.
How can I check for the URL to be malformed or not?
For example :
url = 'google' # Malformed url = 'google.com' # Malformed url = 'http://google.com' # Valid url = 'http://google' # Malformed
Источник: https://stackoverflow.com/questions/716 ... med-or-not
