Hibernate 6 и общее поле JSON ⇐ JAVA
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Anonymous
Hibernate 6 и общее поле JSON
I am using PostgreSQL and Hibernate 6, and I have a JSONB type column - values.
The question is, how can I define an entity with generic type for this field? Also, is there any way to map the correct class during deserialization based on the second ENUM field - type?
Something like:
@Getter @Setter @Entity @Table(name = "setting") public class SettingEntity { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) private Long id; @Enumerated(EnumType.STRING) private SettingType type; @JdbcTypeCode(SqlTypes.JSON) private T values; } I can't find a clear explanation of how to do that. Thanks for any assistance.
Источник: https://stackoverflow.com/questions/772 ... json-field
I am using PostgreSQL and Hibernate 6, and I have a JSONB type column - values.
The question is, how can I define an entity with generic type for this field? Also, is there any way to map the correct class during deserialization based on the second ENUM field - type?
Something like:
@Getter @Setter @Entity @Table(name = "setting") public class SettingEntity { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) private Long id; @Enumerated(EnumType.STRING) private SettingType type; @JdbcTypeCode(SqlTypes.JSON) private T values; } I can't find a clear explanation of how to do that. Thanks for any assistance.
Источник: https://stackoverflow.com/questions/772 ... json-field
