class student
{
int studentID;
String name;
student(int studentID, String name)
{
this.studentID =studentID;
this.name =name;
}
/* Comment this part and run code
public String toString()
{
return studentID + " "+name;
}
The toString method for class Object returns a string consisting of the name of the class of which the object is an instance, the at-sign character `@',
and the unsigned hexadecimal representation of the hash code of the object. In other words, this method returns a string equal to the value of: getClass().getName() + '@' + Integer.toHexString(hashCode())
The Objects. toIdentityString method returns the string for an object equal to the string that would be returned if neither the toString nor hashCode methods were overridden by the object's class.
*/
}
public class toStringMethod
{
public static void main(String[] args)
{
student s = new student(1,"Bruce");
student s2 = new student(2, "Jackie");
System.out.println(s.toString());
System.out.println(s2.toString());
}
}
< /code>
o /p:
Student@6acbcfc0
@5f184fc6
Я не понимаю, почему вывод показывает, как это
Студент@6ACBCFC0
student@5f184fc6.
Excected output,
1 bruce
2 Jackie < /em> < /p>
Подробнее здесь: https://stackoverflow.com/questions/794 ... g-accurate
