File "/Library/Python/2.7/site-packages/flask/app.py", line 1836, in __call__
return self.wsgi_app(environ, start_response)
File "/Library/Python/2.7/site-packages/flask/app.py", line 1820, in wsgi_app
response = self.make_response(self.handle_exception(e))
File "/Library/Python/2.7/site-packages/flask/app.py", line 1403, in handle_exception
reraise(exc_type, exc_value, tb)
File "/Library/Python/2.7/site-packages/flask/app.py", line 1817, in wsgi_app
response = self.full_dispatch_request()
File "/Library/Python/2.7/site-packages/flask/app.py", line 1478, in full_dispatch_request
response = self.make_response(rv)
File "/Library/Python/2.7/site-packages/flask/app.py", line 1577, in make_response
rv = self.response_class.force_type(rv, request.environ)
File "/Library/Python/2.7/site-packages/werkzeug/wrappers.py", line 841, in force_type
response = BaseResponse(*_run_wsgi_app(response, environ))
File "/Library/Python/2.7/site-packages/werkzeug/wrappers.py", line 57, in _run_wsgi_app
return _run_wsgi_app(*args)
File "/Library/Python/2.7/site-packages/werkzeug/test.py", line 867, in run_wsgi_app
app_rv = app(environ, start_response)
TypeError: 'Query' object is not callable
Как выбрать и вернуть только столбец «id»? Я пробовал и другие способы, но тоже безуспешно. Является ли «load_only» правильным вариантом?
[code]File "/Library/Python/2.7/site-packages/flask/app.py", line 1836, in __call__ return self.wsgi_app(environ, start_response) File "/Library/Python/2.7/site-packages/flask/app.py", line 1820, in wsgi_app response = self.make_response(self.handle_exception(e)) File "/Library/Python/2.7/site-packages/flask/app.py", line 1403, in handle_exception reraise(exc_type, exc_value, tb) File "/Library/Python/2.7/site-packages/flask/app.py", line 1817, in wsgi_app response = self.full_dispatch_request() File "/Library/Python/2.7/site-packages/flask/app.py", line 1478, in full_dispatch_request response = self.make_response(rv) File "/Library/Python/2.7/site-packages/flask/app.py", line 1577, in make_response rv = self.response_class.force_type(rv, request.environ) File "/Library/Python/2.7/site-packages/werkzeug/wrappers.py", line 841, in force_type response = BaseResponse(*_run_wsgi_app(response, environ)) File "/Library/Python/2.7/site-packages/werkzeug/wrappers.py", line 57, in _run_wsgi_app return _run_wsgi_app(*args) File "/Library/Python/2.7/site-packages/werkzeug/test.py", line 867, in run_wsgi_app app_rv = app(environ, start_response) TypeError: 'Query' object is not callable [/code]
Как выбрать и вернуть только столбец «id»? Я пробовал и другие способы, но тоже безуспешно. Является ли «load_only» правильным вариантом?