Получение ошибки весной при сохранении объекта ⇐ JAVA

[Anonymous]

Я получаю сообщение об ошибке при сохранении сущности пользователя весной с помощью jpa/hibernate. Ниже приведен мой класс сущности пользователя

Код: Выделить всё

@Entity
@Table(name = "user")
@Data
@FieldDefaults(level = AccessLevel.PRIVATE)
public class User extends Auditable {

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
Integer id;

@Column(name = "name")
String name;

@Column(name = "email", nullable = false)
@Email
String email;

@Column(name = "user_type", nullable = false)
@Enumerated(EnumType.STRING)
UserType userType;

@OneToOne(fetch = FetchType.LAZY, cascade = CascadeType.ALL)
@JoinColumn(name = "address_id")
@ToString.Exclude
Address address;

@Column(name = "active", nullable = false)
Boolean active = false;

@Column(name = "phone_number", nullable = false)
@Pattern(regexp = "^\\d{10}$", message = "Phone number must be exactly 10 digits")
String phoneNumber;

@OneToOne(fetch = FetchType.LAZY, cascade = CascadeType.ALL)
@JoinColumn(name = "company_id")
@ToString.Exclude
CompanyInformation companyInformation;

@Column(name = "hashed_password", nullable = false)
String hashedPassword;

@Column(name = "kyc_done")
Boolean kycDone = false;
}

и ниже приведены мои объекты «Адрес» и «Информация о компании».

Код: Выделить всё

@Entity
@Table(name = "address")
@Data
@FieldDefaults(level = AccessLevel.PRIVATE)
public class Address extends Auditable {

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
Integer id;

@OneToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "user_id", nullable = false)
@ToString.Exclude
User user;

@Column(name = "name", nullable = false)
String addressName;

@Column(name = "address1", nullable = false)
String address1;

@Column(name = "address2", nullable = false)
String address2;

@Column(name = "zipCode", nullable = false)
String zipCode;

@Column(name = "country", nullable = false)
@Enumerated(EnumType.STRING)
Country country;

@Column(name = "state", nullable = false)
@Enumerated(EnumType.STRING)
State state;

@Column(name = "email")
String email;
}

@Entity
@Table(name = "company_info")
@Data
@FieldDefaults(level = AccessLevel.PRIVATE)
public class CompanyInformation extends Auditable {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
Integer id;

@OneToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "user_id")
@ToString.Exclude
User user;

@Column(name = "company_name", nullable = false)
String companyName;

@Column(name = "company_type", nullable = false)
String companyType;

@Column(name = "company_gst")
String gstNumber;

@Column(name = "company_pan", nullable = false)
String panCardNumber;
}

Но я получаю ошибку ниже

Код: Выделить всё

    2024-11-26 01:28:11.399 ERROR 97993 --- [nio-9090-exec-1] o.h.engine.jdbc.spi.SqlExceptionHelper   : Column 'user_id' cannot be null
2024-11-26 01:28:11.608 ERROR 97993 --- [nio-9090-exec-1] c.f.c.exception.CustomExceptionHandler   : exception occurred: could not execute statement; SQL [n/a]; constraint [null]; nested exception is org.hibernate.exception.ConstraintViolationException: could not execute statement

org.springframework.dao.DataIntegrityViolationException: could not execute statement; SQL [n/a]; constraint [null]; nested exception is org.hibernate.exception.ConstraintViolationException: could not execute statement

Я получаю эту ошибку для сущности CompanyInformation, а не для сущности Address, хотя я определил их одинаково.
Я новичок в Spring . Что мне попробовать дальше?

Подробнее здесь: https://stackoverflow.com/questions/792 ... ing-entity